Let A be a ring and I be an ideal, the followings are equivalent conditions to say that I is prime
- I is prime if ab∈I than a∈I or b∈I for all a,b∈A
- I is prime if A/I is an integral domain
Proof
Backward
Let A/I be an integral domain, that's say if x,y∈A/I and xy=0, then x=0 or y=0. Let (a+I)(b+I) be the zero element of I (i.e. (0∈A)+I), then ab+I=I. Hence a+I=I or b+I=I, implies a∈I or b∈I.
Forward
Let I be a prime ideal, let
(a+I)(b+I)=0+I=I
then ab∈I and therefore, a∈I or b∈I. Hence a+I or b+I is the zero coset in A/I.