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Proposition. nilpotent maps form a prime ideal [math-6W2V]

Definition. Coprimary [local-0]

Let AA be a Noetherian ring. A nonzero finitely generated AA-module MM is coprimary if for all aAa \in A, the multiplication map (reuse element aa to denote it)

a:MMxaxa : M \to M \\ x \mapsto ax

is injective or nilpotent.

If MM is coprimary, then the set

P:={aAa is nilpotent}P := \{ a \in A \mid a \text{ is nilpotent} \}

forms a prime ideal in AA.

Proof. [local-1]

To check PP is a prime ideal, we want to check that if a∉Pa \not\in P and b∉Pb \not\in P then ab∉Pab \not\in P.

Because MM is coprimary, so such a,ba, b are injective, and

(ab)(x)=a(b(x))(ab)(x) = a(b(x))

the composition of injective maps is injective, hence ab∉Pab \not\in P.